HAVING 子句
发表于 2018-3-7 16:03:47 | 分类于 SQL |
HAVING 子句
在 SQL 中增加 HAVING 子句原因是,WHERE 关键字无法与聚合函数一起使用。
HAVING 子句可以筛选分组后的各组数据。
语法
SELECT column_name, aggregate_function(column_name)
FROM table_name
WHERE column_name operator value
GROUP BY column_name
HAVING aggregate_function(column_name) operator value;
示例
"Websites" 表的数据:
+----+--------------+---------------------------+-------+---------+
| id | name | url | alexa | country |
+----+--------------+---------------------------+-------+---------+
| 1 | Google | https://www.google.cm/ | 1 | USA |
| 2 | 淘宝 | https://www.taobao.com/ | 13 | CN |
| 3 | 菜鸟教程 | http://www.runoob.com/ | 4689 | CN |
| 4 | 微博 | http://weibo.com/ | 20 | CN |
| 5 | Facebook | https://www.facebook.com/ | 3 | USA |
| 7 | stackoverflow | http://stackoverflow.com/ | 0 | IND |
+----+---------------+---------------------------+-------+---------+
"access_log" 网站访问记录表的数据:
mysql> SELECT * FROM access_log;
+-----+---------+-------+------------+
| aid | site_id | count | date |
+-----+---------+-------+------------+
| 1 | 1 | 45 | 2016-05-10 |
| 2 | 3 | 100 | 2016-05-13 |
| 3 | 1 | 230 | 2016-05-14 |
| 4 | 2 | 10 | 2016-05-14 |
| 5 | 5 | 205 | 2016-05-14 |
| 6 | 4 | 13 | 2016-05-15 |
| 7 | 3 | 220 | 2016-05-15 |
| 8 | 5 | 545 | 2016-05-16 |
| 9 | 3 | 201 | 2016-05-17 |
+-----+---------+-------+------------+
查找总访问量大于 200 的网站。
SELECT Websites.name, Websites.url, SUM(access_log.count) AS nums FROM (access_log
INNER JOIN Websites
ON access_log.site_id=Websites.id)
GROUP BY Websites.name
HAVING SUM(access_log.count) > 200;
输出结果:
mysql> SELECT Websites.name, Websites.url, SUM(access_log.count) AS nums FROM (access_log
-> INNER JOIN Websites
-> ON access_log.site_id=Websites.id)
-> GROUP BY Websites.name
-> HAVING SUM(access_log.count) > 200;
+----------+-------------------------------+------------+
| name | url | nums |
+----------+-------------------------------+------------+
| Facebook | https://www.facebook.com/ | 750 |
| Google | https://www.google.cm/ | 275 |
| 菜鸟教程 | http://www.runoob.com/ | 521 |
+----------+-------------------------------+------------+
查找总访问量大于 200 的网站,并且 alexa 排名小于 200。
SELECT Websites.name, SUM(access_log.count) AS nums FROM Websites
INNER JOIN access_log
ON Websites.id=access_log.site_id
WHERE Websites.alexa < 200
GROUP BY Websites.name
HAVING SUM(access_log.count) > 200;
输出结果:
mysql> SELECT Websites.name, SUM(access_log.count) AS nums FROM Websites
-> INNER JOIN access_log
-> ON Websites.id=access_log.site_id
-> WHERE Websites.alexa < 200
-> GROUP BY Websites.name
-> HAVING SUM(access_log.count) > 200;
+--------+-----------+
| name | nums |
+--------+-----------+
|Facebook| 750 |
|Google | 275 |
+--------+-----------+